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Xlinq : get an elements value with VB.Net
From Wiki
First we load the file.
- Dim _File As XElement = XElement.Load(GetFilename)
The next line takes out the Element we want. We don't need to specify the root element(a misstake I made the first time around.)
- Dim _Element As IEnumerable(Of XElement) = From c In _File.Elements("Element") Select c
The last line just takes the value of the element and puts it in a string value.
- _return = _Element.Value.ToString
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